Y=5X+2. Find the point on the line y = 5x + 2 that is closest to the origin. Answer by jim_thompson5910 (35256) ( show source ):
How do you graph y = 5x + 2 using the slope and intercept? Socratic from socratic.org
Looking at we can see that the equation is in slope. Y = 5x + 2 y = 5 x + 2. = 5d/dx [x 2] = 5(2x) =.
Answer By Jim_Thompson5910 (35256) ( Show Source ):
You will get a straight line. The required table will be:. Y = 5x + 2 y = 5 x + 2.
Plot Them On A Graph Sheet.
Looking at we can see that the equation is in slope. Differentiate both sides of the equation. Given the function of y with respect to x;.
Substitute 2 Values For \Displaystyle{X} And Solve For \Displaystyle{Y} In Order To Find Two Points On The Line And Plot Them.
(0,2) ( 0, 2) any line can be graphed. It is a linear function. First change to vertex form by completing the square in order to easily find the vertex explanation:
Find The Properties Of The Given Parabola.
Choose a point that the parallel line will pass through. Find the point on the line y = 5 x + 2 that is closest to the origin. Rewrite the equation in vertex form.
Find The Point On The Line Y = 5X + 2 That Is Closest To The Origin.
You can put this solution on your website! = 5d/dx [x 2] = 5(2x) =. How do you find the vertex, x and y intercepts for y = 4x2 + 4x −8 ?
